MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:
        
Two particles each of mass 1 kg are placed at P and Q such that PO=OQ=L. The gravitational force experienced by another 1 kg mass placed at R where OR=L is ?
one year ago

Answers : (2)

Shubham Pathy
19 Points
							
r= distance of 1kg mass from P =distance of mass 1kg from Q
 
r^2=l^2+l^2 
=>  r=l√2
Now total gravitational force =2F=2GMm/r^2
Here F is force due to one particle
 
 
=2×G×1×1/2l2
= G/ll2
 
one year ago
Ankur Singh
15 Points
							
F(1)= Gm^2/r^2
       =G/2l^2
 F(2)=Gm^2/r^2
        =G/2l^2
 F(net)=√F(1)^2+F(2)^2
            =√(G/2l^2)^2+(G/2l^2)^2
            =√(G^2/4l^4)+(G^2/4l^4)
            =G/l^2√2
 
6 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details