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`        Two particles each of mass 1 kg are placed at P and Q such that PO=OQ=L. The gravitational force experienced by another 1 kg mass placed at R where OR=L is ?`
one year ago

```							r= distance of 1kg mass from P =distance of mass 1kg from Q r^2=l^2+l^2 =>  r=l√2Now total gravitational force =2F=2GMm/r^2Here F is force due to one particle  =2×G×1×1/2l2= G/ll2
```
one year ago
```							F(1)= Gm^2/r^2       =G/2l^2 F(2)=Gm^2/r^2        =G/2l^2 F(net)=√F(1)^2+F(2)^2            =√(G/2l^2)^2+(G/2l^2)^2            =√(G^2/4l^4)+(G^2/4l^4)            =G/l^2√2
```
6 months ago
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