three numbers are chosen at random without replacement from {1,2,3,....10}.the probability that the minimum of the chosen numbers in 3 or their maximum is 7 is

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Arun · Answer

Number of elements in sample space = 10 C 3 =120 According to the question 3 & 7 must get chosen and the third no. should be between them (ie 4 or5 or 6)as per condition . So, no of favourable cases = 3 C 1 =3 Therefore required probablity = 3/120 = 1/40

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three numbers are chosen at random without replacement from {1,2,3,....10}.the probability that the minimum of the chosen numbers in 3 or their maximum is 7 is

three numbers are chosen at random without replacement from {1,2,3,....10}.the probability that the minimum of the chosen numbers in 3 or their maximum is 7 is

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three numbers are chosen at random without replacement from {1,2,3,....10}.the probability that the minimum of the chosen numbers in 3 or their maximum is 7 is

three numbers are chosen at random without replacement from {1,2,3,....10}.the probability that the minimum of the chosen numbers in 3 or their maximum is 7 is

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