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There are 3 bags each containing 5 red and 3 blue balls. Also there are 2 bags each containing 2 red and 4 blue balls. A ball is drawn random. Determine the probability that the red balls is from a bag of 1 st group.

There are 3 bags each containing 5 red and 3 blue balls. Also there are 2 bags each containing 2 red and 4 blue balls. A ball is drawn random. Determine the probability that the red balls is from a bag of 1st group. 

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Grade:12

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
this is a conditional probability question
 
P(A/B) =
A = red ball from bag 1
B = drawn ball is red.
 
P(A/B) = 5/8 /( 5/8 + 2/6 + 2/6 ) = 30 / 62 = 15/31
 
hope it helps
 

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