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Grade 11IIT JEE Entrance Exam

The wavelength corresponding to maximum energy for hydrogen is 91.2 nm. Find the corresponding wavelength for He^+ ion.

Profile image of dee
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago
We know that , 
1/x = R*Z²*[1/(n1)²-1/(n2)²] where x is wavelength.
According to the question , 
1/91.2 = R*1²*[1/(n1)²-1/(n2)²]                        for hydrogen      ..................1
1/x = R*2²*[1/(n1)²-1/(n2)²]                            for helium           ..................2
Dividing the equations 1 and 2, we get,
x/91.2 = 1/4
x = 22.8 nm
 
 

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