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`        									The speed of sound in a gas, in which two waves of wavelength 1.0 m and 1.02 m produce 6 beats per second, is approximately :			 						`
one month ago

Arun
23338 Points
```							Dear Neha As we know 1.02V - 1.00V=6 x 1.020.02 V = 6.12V = 306 m/sec Hope it helps  Thanks. & RegardsArun
```
one month ago
Vikas TU
9762 Points
```							Dear student f1 = v/lambda 1= V/1.00f2 = V/Lambda2 f1 -f2 =  6 0.02V = 6.06V = 6.06 / 0.02 = 303 m/sGood Luck
```
one month ago
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