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The pharse  between difference between the two ways represent by
y1=10^-6sin[100t+x/50+0.5]m
y2=10^-6cos[100t+x/50]m
where x is expressed in metres and t is expressed in sec is approximately
8 months ago

Answers : (1)

Arun
21972 Points
							
The phase difference can be observed if both the expressions are in either cosin or sin . so after converting both in cosin or sin, one can compare both expressions and the difference between the phase of two could be find out.
 
hence y1 = 10^-6 cos (pi/2 – 0.5 – (100t + x/50))
 
hence phase difference = pi/2 – 0.5 = 1.08 radian approximately
8 months ago
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