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The number of ways in which 10 candidates a1 a2 ..... a10 can be ranked such that a1 is always above a10 ?
5 years ago

Answers : (1)

Shubham Singh
199 Points 
							
9! + 8x8! + 8x7x7! + 8x7x6x6! +…......+ 8!
= 9! + 8x8! + 7x8! + 6x8! +...............+ 8!
= 9x8! + 8x8! + 7x8! + 6x8! +...........+8!
=8!(9+8+7+.......+1)
=8!x9x5
=9!x5
5 years ago
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