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The number N = 6 log 2 to the base 10 + log 31 to the base 10 lies between two successive integers whose sum is equal to (1) 5(2) 7(3) 9(4) 10

Ananya , 6 Years ago
Grade 11
anser 2 Answers
Saurabh Koranglekar

Last Activity: 6 Years ago

log of ((2^6)

Saurabh Koranglekar

Last Activity: 6 Years ago

6 log of 2 to base 10 = log of 32 to base 10
 
log of 31 to base 10 be as it is
 
now log of a to base 10 + log of b to base 10 = log of (a*b) to base 10
 
therefore, log of (32*31) to base 10 = 2.9965
 
therefore ans = 2+3
                     option number (1) 5

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