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The number N = 6 log 2 to the base 10 + log 31 to the base 10 lies between two successive integers whose sum is equal to (1) 5 (2) 7 (3) 9 (4) 10

The number N = 6 log 2 to the base 10 + log 31 to the base 10 lies between two successive integers whose sum is equal to 
(1) 5
(2) 7
(3) 9
(4) 10

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
5 years ago
log of ((2^6)
Saurabh Koranglekar
askIITians Faculty 10335 Points
5 years ago
6 log of 2 to base 10 = log of 32 to base 10
 
log of 31 to base 10 be as it is
 
now log of a to base 10 + log of b to base 10 = log of (a*b) to base 10
 
therefore, log of (32*31) to base 10 = 2.9965
 
therefore ans = 2+3
                     option number (1) 5

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