the normal to curve 5x 5 -10x 3 +x+2y+6=0 at the point p(0,3) is tangent to the curve at the points. find those points.

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Anish Singhal · Answer

First find out the eqn of normal, you can do it easily find -1/(dy/dx) then find eqn of normal and then check how many times that line is intersecting with curve.

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the normal to curve 5x 5 -10x 3 +x+2y+6=0 at the point p(0,3) is tangent to the curve at the points. find those points.

the normal to curve 5x⁵-10x³+x+2y+6=0 at the point p(0,3) is tangent to the curve at the points. find those points.

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the normal to curve 5x 5 -10x 3 +x+2y+6=0 at the point p(0,3) is tangent to the curve at the points. find those points.

the normal to curve 5x5-10x3+x+2y+6=0 at the point p(0,3) is tangent to the curve at the points. find those points.

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the normal to curve 5x⁵-10x³+x+2y+6=0 at the point p(0,3) is tangent to the curve at the points. find those points.