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The moment of inertia of a meter scale of mass 0.6kg about an axis perpendicular to the scale and located at the 20cm position on the scale in kgm² is?
The moment of inertia of a meter scale of mass 0.6kg about an axis perpendicular to the scale and located at the 20cm position on the scale in kgm² is?

```
3 years ago

Arun
25768 Points
```							Using the Parallel Axis Theorem, the Moment of Inertia about an axis at an distance of 20 cm from its centre is given as,   I = ML²/12 + Ma² Now, Using the conditions, given in Questions,   M = 0.6 kg, L = 1 m. a = 20/100 m = 0.2 m. Substituting these values in the Formula, we will get, I = 0.6 (1²/12 + 0.2²) ∴ I = 0.6(1/12 + 4/100) ∴ I = 0.6(0.0833 + 0.04) ∴ I = 0.6 × 0.123 ∴ I = 0.074 kg-m².
```
7 months ago
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