badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

The moment of inertia of a meter scale of mass 0.6kg about an axis perpendicular to the scale and located at the 20cm position on the scale in kgm² is?

2 years ago

Answers : (1)

Arun
24735 Points
							
Using the Parallel Axis Theorem,
 
the Moment of Inertia about an axis at an distance of 20 cm from its centre is given as,
 
  I = ML²/12 + Ma²
 
Now,
 
Using the conditions, given in Questions,
 
  M = 0.6 kg, L = 1 m.
 
a = 20/100 m = 0.2 m.
 
Substituting these values in the Formula, we will get,
 
I = 0.6 (1²/12 + 0.2²)
 
∴ I = 0.6(1/12 + 4/100)
 
∴ I = 0.6(0.0833 + 0.04)
 
∴ I = 0.6 × 0.123
 
∴ I = 0.074 kg-m².
 
4 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details