The locus of the orthocentre of a triangle formed by the line (1+p)-py+p(1+p)=0,(1+q)-qy+(1+q)=0,x=0p≠q is a straight line of slope is

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Arun · Answer

Dear student Question is incorrect as all the lines are parallel to y axis ahence no triangle is formed. Please check and repost the question. You can also attach an image

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The locus of the orthocentre of a triangle formed by the line (1+p)-py+p(1+p)=0,(1+q)-qy+(1+q)=0,x=0p≠q is a straight line of slope is

The locus of the orthocentre of a triangle formed by the line (1+p)-py+p(1+p)=0,(1+q)-qy+(1+q)=0,x=0p≠q is a straight line of slope is

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The locus of the orthocentre of a triangle formed by the line (1+p)-py+p(1+p)=0,(1+q)-qy+(1+q)=0,x=0p≠q is a straight line of slope is

The locus of the orthocentre of a triangle formed by the line (1+p)-py+p(1+p)=0,(1+q)-qy+(1+q)=0,x=0p≠q is a straight line of slope is

1 Answers

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