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`        The fraction (5x-11)/(2x2 + x - 6) was obtained by adding the two fractions A/(x + 2) and B/(2x - 3). The values of A and B must be, respectively:(a) 5x, -11, (b) -11, 5x, (c) -1, 3, (d) 3, -1, (e) 5, -11`
2 years ago

Nandana
110 Points
```							option (d) is currectSol : –A(2x-3) + B(x+2) = 2Ax-3A+Bx+2B /(2X^2+4X-3X-6)= x(2A+B)-(3A-2B) /( 2X^2+4X-3X-6)equate right hand side & left hand sides , then denominator is same & equilate the numerator  coefficients , we get2A+B = 53A-2B = 11by solving these equations we get A=3 & B=-1
```
2 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions