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IIT JEE Entrance Exam

The equations x-y=4, x^2+4xy+y^2=0 represent sides of
1.equilateral triangle 2.right angled triangle 3.isosceles triangle

Pradeep M R

7 Years agoGrade

2 Answers

Manda Snehashish Reddy

7 Years ago

Please find your answer below

REGARDS, Ashish

NOTE: As you are as aspirant, I’d rather suggest you to solve the equations yourself. Do it yourself like many others to improve your speed and accuracy.

Manda Snehashish Reddy

7 Years ago

x-y = 4
x²+4xy+y²=0
Simplifying the above equation
x²+4xy+y²+3y²=3y²
(x+2y)² =3y²
y =(3^1/2 -2)x or y = -(3^1/2+2)x
These two lines intersect at (0,0)
x-y=4 intersects with x²+4xy+y²=0 at (0.845,-3.155) and (3.155,-0.845)

Lengths of the sides are 3.266,3.266,3.266

Therefore the triangle is an equilateral triangle.

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