The displacement x of a body of mass 1 kg on a horizontal smooth surface has the function of the time t is given by x=t⁴/4. The work done in first one second is

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Arun · Answer

x = t^4 / 4 meters m = 1 kg dx = t²^3dt dx/dt = v = t^3 d²x/dt² = a = 3 t^2 force acting on the body = m a = 3 t^2 Newtons now fornwork done integrate F. dx

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The displacement x of a body of mass 1 kg on a horizontal smooth surface has the function of the time t is given by x=t⁴/4. The work done in first one second is

The displacement x of a body of mass 1 kg on a horizontal smooth surface has the function of the time t is given by x=t⁴/4. The work done in first one second is

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The displacement x of a body of mass 1 kg on a horizontal smooth surface has the function of the time t is given by x=t⁴/4. The work done in first one second is

The displacement x of a body of mass 1 kg on a horizontal smooth surface has the function of the time t is given by x=t⁴/4. The work done in first one second is

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