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`        The circle x^2+y^2=4 cuts the circle x^2+y^2+2x+3y-5=0 in A&B.Then the equation of circle on AB as diameter is?I tried this by family of circles but didn't got the answer. Please help`
one year ago

Arun
22984 Points
```							Dear student by family of circle S1 + a S2 = 0 x^2 (1 + a) + y^2 (1+a) + 2ax + 3ay – 5a – 4 = 0 x^2 + y^2  + 2ax/(1+a) + 3ay/ (1+a) –( 5a + 4)/(1+a) = 0  now s1 – S2 = 0 2x + 3y – 1 = 0 now centre of circle passes thriugh this line then you will get a
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions