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`        The acute angle	bisector between the lines 3x - 4y - 5 = 0? from image please give me idea `
2 years ago

Arun
23755 Points
```							Dear shubhamFirst make c1 and c2 of both equations positive-(3x -4y -5).  And  -(5x +12y -26)Now a1*a2 + b1* b2Equation of acute angle bisector is(3x -4y - 5)/5 = (5x +12y -26)/1339x -52y -65 = 25x +60 y -13014x - 112y +65 = 0Hence option 3 is correct.RegardsArun (askIITians forum expert)
```
2 years ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions