Arun
Last Activity: 4 Years ago
Parameterize parabola as (at²,2at) so tangent at t is ty=x+at²
For points P(p) & Q(q) tangents are py=x+ap² & qy=x+aq²
Solving for intersection gives y=a(p+q), x=apq
If this point lies on x+4a=0 then pq=−4 … (i)
But if OP⊥OQ then 2ap/(ap²) * 2aq/(aq²) = −1 → pq=−4 which is true because of (i).
∴ ∠POQ=90°