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Grade: 11

                        

Solve the marked question with explanation in a paper page and please UK pload fast

one month ago

Answers : (1)

Vikas TU
12280 Points
							
Dear student 
y = l^2 – l^3 /z
so, max m value of l = 2.1 min value of l = 1.9 
max value of z = 1.1 , min value of z = 0.9 
y = 2.1^2 – 2.1^3 / 1.1 = 4.41- 9.261 /1.1 = -4.009 
Taking min value 
1.9^2 – 1.9^3/ 0.9 = 3.61 – 7.62 = -4.011 
so the range is -4.0 + or minus 0.8 
you can check putting minus value too. 
Hope this will help 
Good Luck 
one month ago
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