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solve the equation sin6x + cos4x + 2 = 0 ,find all the solutions of the equation sinx + (sin 180/8) sqrt of (squre of 1- cosx + squre of sinx )

solve the equation sin6x + cos4x + 2 = 0   ,find all the solutions of the equation sinx + (sin 180/8) sqrt of (squre of  1- cosx + squre of sinx )

Grade:12

2 Answers

Arun
25750 Points
4 years ago
Dear student
 
it can be written as
 
3 sin2x – 4 sin^3 2x – 2 sin^2 2x + 3 = 0
 
now this is cubic in sin 2x
 
on factorisation we get that sin 2x = 1 is only factor
 
hence sin 2x = 1
2x = (4n+1)pi/2
x = (4n+1)pi/4
Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

Expand sin 6 x as 3 ( theta)
Expand cos 4x as 2( theta) specifically in sine term

Consider sin 2x as some variable m

Solve for cubic eqn m and substitute m as originally considered sin 2x

Simplify to get final solution

Kindly refrain from asking multiple questions in one thread

Thanks and regards

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