
Grade 11IIT JEE Entrance Exam
So, n = 2.41 J/688 mJ
= (2.41 J/688 mJ) (1 mJ/10-3 J)
= 3.50
So, n = 2.41 J/688 mJ
= (2.41 J/688 mJ) (1 mJ/10-3 J)
= 3.50

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-
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