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sir in this question we have used equation G=nFE to get the E of resultant reaction but, sir in 2014 jee main (offline) their was same question and we have just added or subtracted the two reactions to get the E of the resultant. Sir please clear my doubt i have attached the image of question which came in AIEEE 2009 in which G=nFE is used ?

Sitanshu Yadav , 5 Years ago
Grade 11
anser 2 Answers
Samyak Jain

Last Activity: 5 Years ago

Actually, E\degree  is an intensive property while \DeltaG\degree is an extensive property. This implies E\degree cannot be just added
whereas \DeltaG\degree can be added for reactions. However, the potentials are additive when half-reations are added to yield an overall reaction but they aren’t additive when half-reactions are added to give third half-reaction.
.\degree = -nFE\degreeG\DeltaIn 2014 JEE Main (offline), the two half reactions were added to giveoverall reaction (in which no electrons were present). So E\degree could be added.But here the two reactions yield third half reaction (in which electron is present) and thus we need to proceed through

Samyak Jain

Last Activity: 5 Years ago

Error occured while answering earlier. Here is the answer.
Actually, E\degree  is an intensive property while \DeltaG\degree is an extensive property. This implies E\degree cannot be just added whereas \DeltaG\degree can be added for reactions. However, the potentials are additive when half-reations are added to yield an overall reaction but they aren’t additive when half-reactions are added to give third half-reaction.
In 2014 JEE Main (offline), the two half reactions were added to giveoverall reaction (in which no electrons were present). So E\degree could be added. But here the two reactions yield third half reaction (in which electron is present) and thus we need to proceed through \DeltaG\degree = -nFE\degree.

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