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Grade 12Differential Calculus

Sir explain method of this type concept
.........,...................................thanks

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Profile image of Kishan Kushavaha
7 Years agoGrade 12
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1 Answer

Profile image of yathartha gupta
7 Years ago
Given limitx---->0 sin(πx/2)^2x .   & .  [0,2]
Put 0 at the place of x
 Thus limitx------>0 sin 0 =0-------------1
Put 2 at the place of x
 Thus limitx-------->0 sin(2π/2)^4=limitx-------->0
(sin(π))^4=0--------------2
    Although equation 1 & 2 are same hence the given function will continuous in the given intervel