Question is from class 11 Simple harmonic motion. Please see the attached image for the same
Question is from class 11 Simple harmonic motion. Please see the attached image for the same
Rajan Thakur , 7 Years ago
Grade
IIT JEE Entrance Exam> Question is from class 11 Simple harmonic...
1 AnswersVikas TU
Dear student
We know that the time period of an object,
T = 2π√(I/mgL)
where ,
I = moment of inertia from the suspended point
L = distance of its centre from suspended point = r
we know that, the moment of inertia of disc about its centre = mr²/2
using parallel axis theoram the moment of inertia from a point in its periphery,
I = mr² + mr²/2 = 3mr²/2
putting the values in the above equation we get,
T = 2π√(3mr²/2mgr)
= 2π√(3r/2g)
Hence the time period of the disc is 2π√(3r/2g)
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