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Grade: 12 
        
Prove v=vmsinomega t =2vm/pi for half period of its cycle
2 years ago

Answers : (1)

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Nandana
110 Points 
							
 
1/pi ∫0pivm sin (wt) dt
= vm/pi [ -cos (wt)/w ]0pi
= vm/ pi (2)
=> 2 vm/pi                   
this is due to the average of the above function .
2 years ago
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