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Prove v=vmsinomega t =2vm/pi for half period of its cycle

Prove v=vmsinomega t =2vm/pi for half period of its cycle

Grade:12

1 Answers

Nandana
110 Points
7 years ago
 
1/pi 0pivm sin (wt) dt
= vm/pi [ -cos (wt)/w ]0pi
= vm/ pi (2)
=> 2 vm/pi                   
this is due to the average of the above function .

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