Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Prove that though covariance is independent of the choice of origin, it depends upon the scale. If u=ax+b, v=cy+d, show that cov(u,v)=a.c. cov(x,y).`
5 months ago

Saurabh Koranglekar
4185 Points
```							Dear studentCov(x,y) = E((x-m(x))(y-m(y))), where m() is the mean.Let u = ax + b and v = cy + dSo, Cov(u, v) = E((u-M(u))(v-M(v)))= E((ax + b - (am(x) + b))(cy + d - (cm(y) + d))=E((ax - am(x))(cy - cm(y)))=acE(x - m(x))(y - m(y)))=acCov(x,y)Regards
```
2 months ago
Vikas TU
10599 Points
```							Dear student For more information , Please refer the study material https://www.askiitians.com/revision-notes-new/maths/statistics/Good Luck Cheers
```
one month ago
Think You Can Provide A Better Answer ?

## Other Related Questions on IIT JEE Entrance Exam

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions