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plz solve check picture in attachment !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1 !!!!!!!!!!!!!!!!!!!!!!!!!!!

plz solve  check picture in attachment
 
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Grade:12th pass

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Dear student,

Energy of an orbit\propto \dfrac{1}{n^2}
Hence energy second orbit=-1.51eV\times \dfrac{3^2}{2^2}=-3.4eV'
Therefore energy emitted by transition3\rightarrow 2is3.4eV-1.51eV=1.89eV

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