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Grade 11IIT JEE Entrance Exam

Plz answer the attached question....................

Question image for Plz answer the attached question.................

nagashravan hemadri

8 Years agoGrade 11

1 Answer

Arun

8 Years ago

C). When radius is by ∆R,

4πR²∆RpL = 4πT[R² – (R - ∆R]

$\Rightarrow$ pR²∆RL = T[R² – R² + 2R∆R - ∆R^2]

$\Rightarrow$ pR²∆RL =T2R∆R [ ∆R is very small ]

$\Rightarrow$ R = 2T/pL

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