Grade 12IIT JEE Entrance Exam
Please upload solution of this question of Rotation.
Please upload solution of this question of Rotation.
1 Answer
Arun
I
C
(perpendicular to plane) =
2
1
mR
2
I
OB
=
4
1
mR
2
I
PQ
=
4
1
mR
2
+m
16
R
2
=
16
5
mR
2
Total energy is conserved.
P.E
i
+K.E
i
=P.E
f
+K.E
f
mg×
4
5R
+mg×
4
R
+0=mg×
4
−5R
+mg×
4
−R
+
2
1
I
PQ
w
2
+
2
1
mv
2
mg×
2
5R
+mg×
2
R
=
2
1
×
16
5
mR
2
w
2
+
2
1
mv
2
As v=
4
5R
3mgR=
2
1
×
16
5
mR
2
×
25R
2
16v
2
+
2
1
mv
2
3mgR=
10
1
mv
2
+
2
1
mv
2
⟹v=
5gR
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