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Grade: 12th Pass 
        
Please solve the above mentioned question with required explanation.
one year ago

Answers : (2)

View Solution
Eshan
askIITians Faculty
2095 Points 
							Dear student,

Work done by gas in a process is area under the P-V curve.

Work done by gas from A to B=P_0(2V_0-V_0)=P_0V_0
Work done by gas from B to C (isothermal process)=nRTln(\dfrac{4V_0}{2V_0})=(2P_0V_0)ln2=2P_0V_0ln2
Work done by gas from C to D =(\dfrac{P_0}{2})(2V_0-4V_0)=-P_0V_0
Hence total work done by gas=2P_0V_0ln 2
Hence work done on the gas=-2P_0V_0ln 2
one year ago
View Solution
Eshan
askIITians Faculty
2095 Points 
							Dear student,

Work done by gas in a process is area under the P-V curve.

Work done by gas from A to B=P_0(2V_0-V_0)=P_0V_0
Work done by gas from B to C (isothermal process)=nRTln(\dfrac{4V_0}{2V_0})=(2P_0V_0)ln2=2P_0V_0ln2
Work done by gas from C to D =(\dfrac{P_0}{2})(2V_0-4V_0)=-P_0V_0
Hence total work done by gas=2P_0V_0ln 2
Hence work done on the gas=-2P_0V_0ln 2
one year ago
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