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Please solve the above mentioned question with required explanation.

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2 years ago

Eshan
2095 Points
```							Dear student,Work done by gas in a process is area under the P-V curve.Work done by gas from A to B=$P_0(2V_0-V_0)=P_0V_0$Work done by gas from B to C (isothermal process)=$nRTln(\dfrac{4V_0}{2V_0})=(2P_0V_0)ln2=2P_0V_0ln2$Work done by gas from C to D =$(\dfrac{P_0}{2})(2V_0-4V_0)=-P_0V_0$Hence total work done by gas=$2P_0V_0ln 2$Hence work done on the gas=$-2P_0V_0ln 2$
```
2 years ago
Eshan
2095 Points
```							Dear student,Work done by gas in a process is area under the P-V curve.Work done by gas from A to B=$P_0(2V_0-V_0)=P_0V_0$Work done by gas from B to C (isothermal process)=$nRTln(\dfrac{4V_0}{2V_0})=(2P_0V_0)ln2=2P_0V_0ln2$Work done by gas from C to D =$(\dfrac{P_0}{2})(2V_0-4V_0)=-P_0V_0$Hence total work done by gas=$2P_0V_0ln 2$Hence work done on the gas=$-2P_0V_0ln 2$
```
2 years ago
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