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`        Please solve question number 17 ???????!!!!!!!!!!!!!`
one year ago

Sahani Kumar
99 Points
```							P= atmospheric pressure = 1 * 10^5h= height of the water  p= density of water = 10^3g= acceleration due to gravity                 Pressure at the bottomof the tank =P + hpg  = 3 * 10^5 hpg=(3 *10^5) - (P)         = (3 * 10^5) - (1 *10^5) = 2 * 10^5Now we know that 1/2(p * v^2) = pgh =2 *10^5 So  1/2(p * v^2) = 2 * 10^5             v^2=( 2(2* 10^5))/p = (2(2 * 10^5))/(10^3)             v^2=400             v=√(400)  or 20 m/sRegards Askiitian memberIf you like this answer please encourage us by approving this answer.
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions