in the question , the block below is experiencing two forces , one due to the friction and other due to the tension in that string . also the frictional froce acts in the direction of movement of both of them on block and opposite to that direction on the man . the tension
T=100 N
let n m/s-2 be the common accelaration of the man and the block below man .
AND LET f BE THE FRICTION (WHICH WOULD BE SAME ON BOTH OF THE BLOCK AND MAN .
now by f(net external) = ma
taking the block, we see ,
T-f = ma = 50n
and in the block , we see ,
T+f=ma=100n
adding both the equations above , we get ,
2T=150n therefore, a=4/3 m/s-2 (since T=100N)
substituting this value of n in any of the equations , you can easily get ,
f = 100/3N
hence , the requiered value of X in the question is 3