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Grade 11IIT JEE Entrance Exam

Please explain how rho solve image problem please explain clearly fully..........

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Profile image of Sudhanva G V
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago
Dear student
 

For string

\\l=42\; cm\\d=6\; mm\Rightarrow r=3\; mm\\A=\pi\; r^{2}\\\Delta l=20\; cm

for stone

\\m=0.02\; kg\\V=20\; m/s

So apply energy conservation.

P.E. stored in string = K.E of stone

\Rightarrow \frac{1}{2}\times Y\times \left ( \frac{\Delta L}{L} \right )^{2}\times A\times L=\frac{1}{2}\; mv^{2}

\Rightarrow Y = \frac{mv^{2}\times L}{(\Delta L)^{2}\times A}

            = \frac{2\times 10^{-2}\times 20\times 20\times 42\times 10^{-2}}{20\times 20\times 10^{-4}\times 3.14 \times 9\times 10^{-6} }

      Y\approx 10^{6}\; N/m^{2}

 

Hope it helps

Regards

Arun (askIITians forum expert)