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Grade 12IIT JEE Entrance Exam

Please answer this encircled question .

Question image for Please answer this encircled question .

agam goel

11 Years agoGrade 12

2 Answers

Nishant Vora

11 Years ago

Hello student
Please find the solution
Let [tanx]= t
$\frac{t^2 - 2t -3}{t^2 - 4t +3} = \frac{(t-3)(t+1)}{(t-3)(t-1)} =\frac{(t+1)}{(t-1)}$
So the question becomes
$\lim_{x-> \tan^{-1} 3} {\frac{[\tan^{-1}x +1]}{[\tan^{-1}x - 1]}} = \frac{4}{2} = 2$

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agam goel

11 Years ago

Answer is 1/3.

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