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Please answer this encircled question .

Please answer this encircled question .
 

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Grade:12

2 Answers

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
7 years ago
Hello student
Please find the solution
Let [tanx]= t
\frac{t^2 - 2t -3}{t^2 - 4t +3} = \frac{(t-3)(t+1)}{(t-3)(t-1)} =\frac{(t+1)}{(t-1)}
So the question becomes
\lim_{x-> \tan^{-1} 3} {\frac{[\tan^{-1}x +1]}{[\tan^{-1}x - 1]}} = \frac{4}{2} = 2

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agam goel
35 Points
7 years ago
Answer is 1/3.

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