Arun
Last Activity: 4 Years ago
Moles of HCN = 2.5 moles
Moles of KCN = 0.25 moles
Volume of solution = 500 mL = 0.5 L (Conversion factor: 1 L = 1000 mL)
The chemical reaction for HCN and KOH follows the equation:
To calculate the molarity of solution, we use the equation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of acid dissociation constant of hydrogen cyanide = 9.3
pH = ?
Putting values in above equation, we get:
