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Grade: 12
        
 
P is the remainder when each of the numbers 478, 392, and 263 is divided by N, where N is an integer greater than 1. The value of N – P is:
(A) 5 (B) 28 (C) 33 (D) 38
 
4 years ago

Answers : (5)

Akshay
185 Points
							(D) 38.....N=43,P=5
						
4 years ago
Akshay
185 Points
							(478-P) , (392-P) and (263-P) should be divisible by N.  If 2 numbers are divi
						
4 years ago
Akshay
185 Points
							
(478-P) , (392-P) and (263-P) should be divisible by N. If 2 numbers are divisible by N, then their difference is also divisble by N. Hene, (478-P)-(392-P) is divisible by N. And, (392-P)-(263-P) is divisible by N. So, 86 and 123 are divisble by N. Hence, N can only be 43. And 478=43*11+5. so, P=5.
4 years ago
Akshay
185 Points
							
Sorry, 86 and 129*(not 123)
4 years ago
vindhya
50 Points
							
thanks a lot Mr. Akshay. your answer really helped a lot. May i know, which standard you are in, if you don't mind.
thanks again.
4 years ago
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  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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