0

Guest

Courses New

masses 8,2,4,2kg are placed at the corners A,b,c,d of a square abcd of diagonal 80 cm the distance of centre of mass from A will be ?

masses 8,2,4,2kg are placed at the corners A,b,c,d of a square abcd of diagonal 80 cm the distance of centre of mass from A will be ?

Grade:11

1 Answers

Sarfaraz Ahamed
26 Points
6 years ago
Centre of mass is given by = (m1x1 +m2x2 +m3x3 +m4x4)/(m1+m2+m3+m4)  
where m is the respective mass and x is the respective distance with respect to A ( in metres)
the diagonal of a square is 0.8 metres therefore using pythogoras law each side is of a distance 0.56 metres.
therefore centre of mass is = (8*0+2*0.56+4*0.8+2*0.56)/(8+2+4+2)=.34 metres from A

Think You Can Provide A Better Answer ?

Other Related Questions on IIT JEE Entrance Exam

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More