×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
masses 8,2,4,2kg are placed at the corners A,b,c,d of a square abcd of diagonal 80 cm the distance of centre of mass from A will be ?
masses 8,2,4,2kg are placed at the corners A,b,c,d of a square abcd of diagonal 80 cm the distance of centre of mass from A will be ?

```
3 years ago

Sarfaraz Ahamed
26 Points
```							Centre of mass is given by = (m1x1 +m2x2 +m3x3 +m4x4)/(m1+m2+m3+m4)  where m is the respective mass and x is the respective distance with respect to A ( in metres)the diagonal of a square is 0.8 metres therefore using pythogoras law each side is of a distance 0.56 metres.therefore centre of mass is = (8*0+2*0.56+4*0.8+2*0.56)/(8+2+4+2)=.34 metres from A
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on IIT JEE Entrance Exam

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions