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masses 8,2,4,2kg are placed at the corners A,b,c,d of a square abcd of diagonal 80 cm the distance of centre of mass from A will be ?

Aakash , 7 Years ago
Grade 11
anser 1 Answers
Sarfaraz Ahamed

Last Activity: 7 Years ago

Centre of mass is given by = (m1x1 +m2x2 +m3x3 +m4x4)/(m1+m2+m3+m4)  
where m is the respective mass and x is the respective distance with respect to A ( in metres)
the diagonal of a square is 0.8 metres therefore using pythogoras law each side is of a distance 0.56 metres.
therefore centre of mass is = (8*0+2*0.56+4*0.8+2*0.56)/(8+2+4+2)=.34 metres from A

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