Mass of the bob of a simple pendulum oflength L is m. If the bob is projectedhorizontally from its mean position withvelocity underroot 4gl , then the tension in the stringbecomes zero after a vertical displacement of1)L/3 2)3L/4 3) 4L/3 4) 5L/3

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MeetShah · Answer

U need to use two equations 1 mv^/r =tension -mg cosQ and the second one that of energy conservation That should solve ur problem Thanks!

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Mass of the bob of a simple pendulum oflength L is m. If the bob is projectedhorizontally from its mean position withvelocity underroot 4gl , then the tension in the stringbecomes zero after a vertical displacement of1)L/3 2)3L/4 3) 4L/3 4) 5L/3

Mass of the bob of a simple pendulum oflength L is m. If the bob is projectedhorizontally from its mean position withvelocity underroot 4gl , then the tension in the stringbecomes zero after a vertical displacement of1)L/3 2)3L/4 3) 4L/3 4) 5L/3

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Mass of the bob of a simple pendulum oflength L is m. If the bob is projectedhorizontally from its mean position withvelocity underroot 4gl , then the tension in the stringbecomes zero after a vertical displacement of1)L/3 2)3L/4 3) 4L/3 4) 5L/3

Mass of the bob of a simple pendulum oflength L is m. If the bob is projectedhorizontally from its mean position withvelocity underroot 4gl , then the tension in the stringbecomes zero after a vertical displacement of1)L/3 2)3L/4 3) 4L/3 4) 5L/3

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