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Grade 11IIT JEE Entrance Exam

Is slab consists of two portion of different materials of same thickness and having thermal conductivity is K1 and K2 the equivalent thermal conductivity of slab is

Profile image of Sudhanva G V
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago
Dear student
 
H = H1 + H2 for slabs in parallel. ∆T.KA/L = ∆T.K1.A/2L + ∆T.K2.A/2LHere for k1 and k2 we take A/2. That`s imp. So simplify and get K = K1 + K2 / 2

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