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Integration of 6tan3x , limits [0 , 15] ?
intgrl 6tna3x = 6((ln mod sec3x )/3) limits 0,15 =2( 1 + ln mod cos 45 )
tan3x=-1/3ln cosxtherefore limit from0 to 15-2lncos15thanks and regardssunil kraskIItian faculty
Sorry its: -2(1+ ln mod cos 45)
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