Grade 11IIT JEE Entrance Exam
Integration of 6tan3x , limits [0 , 15] ?
3 Answers
Kinjal Shah
intgrl 6tna3x
= 6((ln mod sec3x )/3) limits 0,15
=2( 1 + ln mod cos 45 )
Sunil Kumar FP
tan3x=-1/3ln cosx
therefore limit from0 to 15
-2lncos15
thanks and regards
sunil kr
askIItian faculty
Kinjal Shah
Approved Tutor Answer12 Years agoSorry its: -2(1+ ln mod cos 45)
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