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Integration of 6tan3x , limits [0 , 15] ?

vinaykumarg4u , 11 Years ago
Grade 11
anser 3 Answers
Kinjal Shah

Last Activity: 11 Years ago

intgrl 6tna3x = 6((ln mod sec3x )/3) limits 0,15 =2( 1 + ln mod cos 45 )
Sunil Kumar FP

Last Activity: 11 Years ago

tan3x=-1/3ln cosx
therefore limit from0 to 15

-2lncos15

thanks and regards
sunil kr
askIItian faculty
Kinjal Shah

Last Activity: 11 Years ago

Sorry its: -2(1+ ln mod cos 45)
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