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Grade: 11 
        Integration of 6tan3x , limits [0 , 15] ?
6 years ago

Answers : (3)

Kinjal Shah
17 Points 
							intgrl 6tna3x
= 6((ln mod sec3x )/3) limits 0,15
=2( 1 + ln mod cos 45 )
6 years ago
Sunil Kumar FP
askIITians Faculty
183 Points 
							tan3x=-1/3ln cosx
therefore limit from0 to 15

-2lncos15

thanks and regards
sunil kr
askIItian faculty
6 years ago
Kinjal Shah
17 Points 
							Sorry its: -2(1+ ln mod cos 45)
6 years ago
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