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Grade 12th passIIT JEE Entrance Exam

In the jee main 2017 the kinetic energy of a particle executing SHM was asked (Question 53 Booklet code D offline paper) but all the graphs had non differentiable points which can`t be a case for a particle executing SHM. So I was trying to apply it for bonus but there was no such option for bonus in the official portal of jee main website. Please help me by telling how can I apply?

Profile image of Utkarsh Dubey
9 Years agoGrade 12th pass
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1 Answer

Profile image of Gowtham
9 Years ago
The question is correct and the graph corresponding to a difference of T/4 on x-axis is the correct answer.
As you can see at time T = T/4 the particle will be at the extreme end. Hence its displacement will be maximum i.e. y = A
Hence applyig this in the formula, KE = 1/2*mw2(A2-x2)
You will get a KE = 0 at the extremes and KE = maximum at the mean positions.
Hope this helped you.

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