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`        In how many ways 3 digit number like XYZ can be formed where Z>Y>X ?`
3 years ago Nishant Vora
IIT Patna
2467 Points
```							x=1y=2 z= 3...9 (7 ways)y=3  z= 4...9 (6 ways)...y=8  z= 9 (1 way)Total : 7+6+...+1x=2y=3  z= 4...9 (6 ways)y=4  z= 5...9 (5 ways)...y=8  z= 9 (1 way)Total : 6+5+...+1...x=6y=7 z= 8,9 (2 ways)y=8, z=1 (1 way)Total : 2+1x =7y = 8 z = 9(1 way)Total : 1Required number of ways = ( 7+6+...+1) + (6+5+...+1) + (5+4+3+2+1) + (4+3+2+1) + (3+2+1) + (2+1) + 1=28+21+15+10+6+3+1= 84
```
3 years ago
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