in an a.p. the sum of `n` terms is 5n square-5n find tenth term
Pranjal Shinde
9 Years agoGrade 10
1 Answer
Jitendra Kumar
9 Years ago
Let $S1$ be the sum of the given AP $\rightarrow S1= 5n2-5n$ First terms is $a1=S1 = 0$ and $S2=a1+a2 =10=> a2 = 10$ So common difference $d = 10$ Thus general term is $an = a1+(n-1)d=10(n-1)$ Hence tenth term is $a10=10(10-1)=90$