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Grade 12th passIIT JEE Entrance Exam

If the sum of the first ten terms of the series (1.3/5)2 +(2.2/5)2+(3.1/5)2+42+(4.4/5)2+................ is (16/5)m then m is equal to

Profile image of dheeraj reddy
8 Years agoGrade 12th pass
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1 Answer

Profile image of Amit
8 Years ago
It can be simplified as (8/5)²+(12/5)²+(16/5)²+....... 10 terms.. Take (4/5)² common from the terms .(16/25){2²+3²+...11²}.Solving the series by adding and subtracting 1², we get:- (16/25){505}.Hence equal to (16/5){101}.. Hence m=101

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