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if the sum of distance of the point from perpendicular lines in a plane is 1 then its locus is a;square b.circle. c,straight line

2 years ago

Answers : (1)

Arun
24742 Points
							
Let the x and y axes be the two perpendicular lines.
Then the distance from the origin will be the distance from the perpendicular lines. 
So then the sum of the distances would be x + y = 1
So in the first quadrant, the locus of points would look like a straight line with points (0,1) and (1,0). 
 

In the second quadrant it would contain (0,1) and (-1,0).
Third quadrant (-1,0) and (0,-1).
and finally in the fourth quadrant (0,-1) and (1,0). 
When you put it all together, it would be a square rotated 45 degrees about the origin, the length of the side of the square would be s = sqrt(2)
 
hence option A is correct
2 years ago
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