If th equation ssin4x - (k+2)sin 2 x - (k+3) =0 has a solution then k must lie in the interval of

Question

If th equation ssin4x - (k+2)sin 2 x - (k+3) =0 has a solution then k must lie in the interval of

Deepak Kumar Shringi · Answer

put sin^2x=t and find value of sin^x in terms of k then as sin^x [0,1] find k by this

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If th equation ssin4x - (k+2)sin 2 x - (k+3) =0 has a solution then k must lie in the interval of

If th equation ssin4x - (k+2)sin²x - (k+3) =0 has a solution then k must lie in the interval of

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If th equation ssin4x - (k+2)sin 2 x - (k+3) =0 has a solution then k must lie in the interval of

If th equation ssin4x - (k+2)sin 2x - (k+3) =0 has a solution then k must lie in the interval of

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If th equation ssin4x - (k+2)sin²x - (k+3) =0 has a solution then k must lie in the interval of