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If tanA and tanB are roots of x^2 - 2x-1=0, then sin^2(A+B) is


3 years ago

Arun
25768 Points
							Given, x2−2x−1=0 x=2⋅1−(−2)±(−2)2−4⋅1(−1)​​ x=1+2​,x=1−2​ ⇒tanA=1+2​,tanB=1−2​ ⇒A=tan−1(1+2​),B=tan−1(1−2​) ⇒A=6721​∘,B=2221​∘ Now, sin2(A+B) =sin2(6721​∘+2221​∘) =sin2(90∘) =1

7 months ago
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• Test paper with Video Solution
• Mind Map
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• Discussion Forum
• Previous Year Exam Questions