Grade 11IIT JEE Entrance Exam
If s=2tcube+3tsquare+2t+8 then the time at which acceleration is zero is
1 Answer
Arun
Dear student
s = 2 t³ + 3t² + 2t +8
Now for acceleration, we have to find d²s/dt²
Hence
v = ds/dt = 6t² + 6t + 2
a = dv/dt = d²s/dt² = 12 t +6
Now put a = 0
12t +6 = 0
Hence
t = -1/2
Since t is in negative sign
Hence acceleration can never be zero
Other Related Questions on iit jee entrance exam
Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-
Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-
iit jee entrance exam
Last Activity: 10 Months ago
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
iit jee entrance exam
Last Activity: 3 Years ago
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
iit jee entrance exam
Last Activity: 4 Years ago
Can class 9th students study syllabus class of 11th
Can class 9th students study syllabus class of 11th
iit jee entrance exam
Last Activity: 4 Years ago