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        If f(x) =(sinx -sina) ÷(cosx-cosa), x≠a           =1            , x=a is continuous, at x=a find a
11 months ago

Arun
22540 Points
							Dear student for continuity Limit and value of function should be same. Now f(a) = 1 limit x tends a f(x) = – tan a hence a = – pi/4  a can be other values too at which tan a = – 1

11 months ago
Bhagyashri verma
24 Points
							Hi, we know, $sin A + sin B = 2 sin((A + B)/2) cos((A- B)/2)$and $cos A - cos B = -2 cos((A + B)/2) cos((A- B)/2)$ so, For function to be continuous limit x-> a f(x) = f(a)hence, LHS$(sinx -sina) /div (cosx-cosa) = 2 sin((a+a)/2) cos(a-a)/2) / -2 cos(a+a)/2 cos(a-a)/2)$ =$-tan a$RHS f(a) =1 for continuity lim x->a LHS = RHS hence  tan a = -1 so, a = $\pi /4$

11 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions