If f(x) =(1+|sinx|) ^(a÷|sinx|) , -π÷6 =b , x=0 =e^(tan2x÷tan3x) , 0 Find a and b so that the function is continuous at x=0

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Aditya Gupta · Answer

RHL= e^(2/3) coz tan2x/tan3x can be written as tan2x/2x*3x/tan3x*2/3 and lim y tends to zero tany/y=1 So b=e^(2/3) For LHL, put |sinx|= z Then we have (1+z)^a/z= e^a So a=2/3

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If f(x) =(1+|sinx|) ^(a÷|sinx|) , -π÷6 =b , x=0 =e^(tan2x÷tan3x) , 0 Find a and b so that the function is continuous at x=0

If f(x) =(1+|sinx|) ^(a÷|sinx|) , -π÷6
=b , x=0
=e^(tan2x÷tan3x) , 0
Find a and b so that the function is continuous at x=0

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If f(x) =(1+|sinx|) ^(a÷|sinx|) , -π÷6 =b , x=0 =e^(tan2x÷tan3x) , 0 Find a and b so that the function is continuous at x=0

If f(x) =(1+|sinx|) ^(a÷|sinx|) , -π÷6 =b , x=0 =e^(tan2x÷tan3x) , 0Find a and b so that the function is continuous at x=0

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If f(x) =(1+|sinx|) ^(a÷|sinx|) , -π÷6
=b , x=0
=e^(tan2x÷tan3x) , 0
Find a and b so that the function is continuous at x=0