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`        If cos9x-2cos6x=2, then general solution of x is?Kindly explain the whole procedure. `
10 months ago

Arun
22545 Points
```							cos6x = 2 (cos3x) ^ 2 - 1 cos9x = 4 (cos3x) ^ 3 - 3 (cos3x). Cos3x considered t = (| T | = ==> 4T ^ 3 - 4T ^ 2 - 3T + 2 = 2 ==> T = 0; . T = -1/2 . T = 3/2 (by type> 1) \$ * \$ With cos 3x = 0 ==> 3x = (Pi) / 2 + k (Pi) ==> x = (Pi) / 6 + k (Pi) / 3 \$ * \$ With cos 3x = -1/2 ==> 3x = - (P) / 3 + k2 (Pi) ==> x = - (P) / 9 + k2 (Pi) / 3
```
10 months ago
Kavya Singh
8 Points
```							The options were:-a) 2kπ+--/6     b) 2π/9(3n+-1)c)2nπ+--/3       d)x€¢The cprreco option in this according to solution will be which one and how?
```
10 months ago
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Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions